x^2+x^2+6x+9=x^2+12x+36

Solution for x^2+x^2+6x+9=x^2+12x+36 equation:

x^2+x^2+6x+9=x^2+12x+36

We move all terms to the left:

x^2+x^2+6x+9-(x^2+12x+36)=0

We add all the numbers together, and all the variables

2x^2+6x-(x^2+12x+36)+9=0

We get rid of parentheses

2x^2-x^2+6x-12x-36+9=0

We add all the numbers together, and all the variables

x^2-6x-27=0

a = 1; b = -6; c = -27;
Δ = b2-4ac
Δ = -62-4·1·(-27)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-12}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+12}{2*1}=\frac{18}{2}
=9
$